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Home/ CMR High School Subjects/High School Chemistry: Free Trial*

G. 12

Chemistry

LS & US

Hello , welcome to QuizTime @ Quantum Solverz!
  • This MCQ  is a great way to help you revise this topic.
  • You will get 10 random questions for 20 minutes each time you take the quiz. Good luck!

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Hello ! Welcome to QuizTime @ Quantum Solverz.

 

 

Quiz Time Over!


G. 12 / LS & US

Chemistry: Free Trial*

MCQs

Welcome to QuizTime @ Quantum Solverz.

1 / 10

1. Electrons in atoms occupy orbitals.

Successive ionization energies can give information about the electronic structure of an element.

Which of the following sets of data showing the first four ionization energies, in $kJ mol^{-1}$, of four elements is most likely to belong to boron?

Sorry, that is incorrect.

The only correct answer is: 801 , 2427 , 3660 , 25,026

  • 1086 , 2353 , 4621 , 6223 is incorrect because this does not show a large increase for the fourth ionization, so it is not in group 3.
  • 900 , 1757 , 14,849 , 21,007 is incorrect because it shows a large increase for the third ionization, so it is in group 2.
  • 578 , 1817 , 2745 , 11,578 is incorrect because it is a group 3 element as it has a large increase for the fourth ionization, but it has a first ionization energy that is lower than that of the correct option. So it is below it in Group 3. So it cannot be Boron.

Correct!

The only correct answer is: 801 , 2427 , 3660 , 25,026

  • 1086 , 2353 , 4621 , 6223 is incorrect because this does not show a large increase for the fourth ionization, so it is not in group 3.
  • 900 , 1757 , 14,849 , 21,007 is incorrect because it shows a large increase for the third ionization, so it is in group 2.
  • 578 , 1817 , 2745 , 11,578 is incorrect because it is a group 3 element as it has a large increase for the fourth ionization, but it has a first ionization energy that is lower than that of the correct option. So it is below it in Group 3. So it cannot be Boron.

2 / 10

2. This question is about atomic structure and the Periodic Table.

Atomic emission spectroscopy provides evidence for the existence of

Sorry, that is incorrect.

The only correct answer is: quantum shells

  • Atoms: This is incorrect because atomic emission spectroscopy does not provide evidence for the existence of atoms.
  • Electrons: This is incorrect because atomic emission spectroscopy does not provide evidence for the existence of electrons.
  • Isotopes: This is incorrect because the evidence for isotopes is provided by mass spectroscopy.

Correct!

The only correct answer is: quantum shells

  • Atoms: This is incorrect because atomic emission spectroscopy does not provide evidence for the existence of atoms.
  • Electrons: This is incorrect because atomic emission spectroscopy does not provide evidence for the existence of electrons.
  • Isotopes: This is incorrect because the evidence for isotopes is provided by mass spectroscopy.

3 / 10

3. This question is about atoms, molecules and ions.

The total number of electrons in all the occupied p orbitals in a chloride ion, $Cl^{-}$, is

Sorry, that is incorrect.

The only correct answer is: 12 

  • 5 is incorrect because this is the number of electrons in the 3p orbitals of the chlorine atom
  • 6 is incorrect because this is only the number of electrons in the 3p orbitals of the chloride ion
  • 18 is incorrect because this is the total number of electrons in the chloride ion, not just those in the p orbitals.

Correct!

The only correct answer is: 12 

  • 5 is incorrect because this is the number of electrons in the 3p orbitals of the chlorine atom
  • 6 is incorrect because this is only the number of electrons in the 3p orbitals of the chloride ion
  • 18 is incorrect because this is the total number of electrons in the chloride ion, not just those in the p orbitals.

4 / 10

4. This question is about ionization energies.

Which set of successive ionization energies is most likely to be associated with the element boron?

Sorry, that is incorrect.

The only correct answer is: 801 , 2,427 , 3,660 , 25,026 , 32,828

  • 738 , 1,451 , 7,733 , 10,541 , 13,629 is incorrect because it is typical of group 2 elements.
  • 1,086 , 2,353 , 4,621 , 6,223 , 37 832 is incorrect because it is typical of group 4 elements.
  • 1,402 , 2,856 , 4,578 , 7,475 , 9 445 is incorrect because it could be for group 5,6,7,8 or transition elements.

Correct!

The only correct answer is: 801 , 2,427 , 3,660 , 25,026 , 32,828

  • 738 , 1,451 , 7,733 , 10,541 , 13,629 is incorrect because it is typical of group 2 elements.
  • 1,086 , 2,353 , 4,621 , 6,223 , 37 832 is incorrect because it is typical of group 4 elements.
  • 1,402 , 2,856 , 4,578 , 7,475 , 9 445 is incorrect because it could be for group 5,6,7,8 or transition elements.

5 / 10

5. This is a question about atoms, isotopes, and ions.

Which of the following pairs of ions is isoelectronic?

Sorry, that is incorrect.

The only correct answer is: $Na^{+}$ and $Mg^{2+}$

  • $N^{3-}$ and $Cl^{-}$ is incorrect because the chloride ion has an extra shell of electrons compared to the nitride ion.
  • $O^{2-}$ and $S^{2-}$ is incorrect because the sulfide ion has an extra shell of electrons compared to the oxide ion.
  • $Na^{+}$ and $K^{+}$ is incorrect because the potassium ion has an extra shell of electrons compared to the sodium ion.

Correct!

The only correct answer is: $Na^{+}$ and $Mg^{2+}$

  • $N^{3-}$ and $Cl^{-}$ is incorrect because the chloride ion has an extra shell of electrons compared to the nitride ion.
  • $O^{2-}$ and $S^{2-}$ is incorrect because the sulfide ion has an extra shell of electrons compared to the oxide ion.
  • $Na^{+}$ and $K^{+}$ is incorrect because the potassium ion has an extra shell of electrons compared to the sodium ion.

6 / 10

6. Which of these isoelectronic ions has the largest ionic radius?

Sorry, that is incorrect.

The only correct answer is: $N^{3-}$

  • $O^{2-}$ is not correct because oxygen has more protons to exert an attractive force to reduce the ionic radius
  • $Na^{+}$ is not correct because sodium has more protons to exert an attractive force to reduce the ionic radius
  • $Al^{3+}$ is not correct because aluminum has more protons to exert an attractive force to reduce the ionic radius

Correct!

The only correct answer is: $N^{3-}$

  • $O^{2-}$ is not correct because oxygen has more protons to exert an attractive force to reduce the ionic radius
  • $Na^{+}$ is not correct because sodium has more protons to exert an attractive force to reduce the ionic radius
  • $Al^{3+}$ is not correct because aluminum has more protons to exert an attractive force to reduce the ionic radius

7 / 10

7. Diamond, graphene and graphite are different forms of carbon.

The structural feature that graphene and graphite have in common is that the carbon atoms are arranged in

Sorry, that is incorrect.

The only correct answer is: hexagonal rings within a layer

  • layers with each atom bonded to four others is not correct because, in the layers of graphite and graphene, the carbon atoms are bonded to three other carbon atoms and not four.
  • hexagonal and pentagonal rings within a layer is not correct because graphite and graphene do not have pentagonal rings within their layers
  • a three-dimensional structure is not correct because graphene is a two-dimensional structure consisting of a single layer

Correct!

The only correct answer is: hexagonal rings within a layer

  • layers with each atom bonded to four others is not correct because, in the layers of graphite and graphene, the carbon atoms are bonded to three other carbon atoms and not four.
  • hexagonal and pentagonal rings within a layer is not correct because graphite and graphene do not have pentagonal rings within their layers
  • a three-dimensional structure is not correct because graphene is a two-dimensional structure consisting of a single layer

8 / 10

8. Which of these compounds would form pent-2-ene only when reacted with concentrated phosphoric acid, $H_{3}PO_{4}$?

Sorry, that is incorrect.

The only correct answer is: $CH_{3}CH_{2}CH(OH)CH_{2}CH_{3}$

  • $CH_{3}CH(OH)CH(CH_{3})_{2}$ is not correct because it will not form pent-2-ene
  • $CH_{2}(OH)CH_{2}CH_{2}CH_{2}CH_{3}$ is not correct because it will only form pent-1-ene
  • $CH_{3}CH_{2}CH_{2}CH(OH)CH_{3}$ is not correct because $CH_{3}CH(OH)CH_{2}CH_{2}CH_{3}$ will also form Pent-1-ene

Correct!

The only correct answer is: $CH_{3}CH_{2}CH(OH)CH_{2}CH_{3}$

  • $CH_{3}CH(OH)CH(CH_{3})_{2}$ is not correct because it will not form pent-2-ene
  • $CH_{2}(OH)CH_{2}CH_{2}CH_{2}CH_{3}$ is not correct because it will only form pent-1-ene
  • $CH_{3}CH_{2}CH_{2}CH(OH)CH_{3}$ is not correct because $CH_{3}CH(OH)CH_{2}CH_{2}CH_{3}$ will also form Pent-1-ene

9 / 10

9. The black smoke produced from the incomplete combustion of alkane fuels is

Sorry, that is incorrect.

The only correct answer is: carbon particulates

  • carbon particulates is incorrect because oxides of nitrogen are not black solids
  • oxides of sulfur is incorrect because oxides of sulfur are not black
  • unburnt hydrocarbons is incorrect because unburnt hydrocarbons are not black solids

Correct!

The only correct answer is: carbon particulates

  • carbon particulates is incorrect because oxides of nitrogen are not black solids
  • oxides of sulfur is incorrect because oxides of sulfur are not black
  • unburnt hydrocarbons is incorrect because unburnt hydrocarbons are not black solids

10 / 10

10. The heterolytic bond fission of a sigma ($\sigma$) bond in an alkane would produce

Sorry, that is incorrect.

The only correct answer is: ions

  • only carbocations is not correct because both anions and cations are produced
  • only free radicals is not correct because homolytic fission produces free radicals
  • free radicals and ions is not correct because homolytic fission produces free radicals and heterolytic fission also produces anions

Correct!

The only correct answer is: ions

  • only carbocations is not correct because both anions and cations are produced
  • only free radicals is not correct because homolytic fission produces free radicals
  • free radicals and ions is not correct because homolytic fission produces free radicals and heterolytic fission also produces anions
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